Download GATE 2013 Admit Card now

Eligible candidates can now download admit cards by signing into their account here.

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Download Admit Card for GATE 2013 Exam

Admit cards can be downloaded 5:00 p.m. onwards from 10th December 2012 instead of the advertised date of 5th December 2012.

Check your application status.

C programming for GATE 2013

Hi friends, this post is for those candidates who are going to appear GATE 2013 exam and those who want to learn C programming. In this month we will learn complete C programming.So check regularly this blog for the posts. Daily one topic will be discussed, if you have any query you can also comment, your queries will be resolved spontaneously.

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GATE 2013 Application Status

After an applicant submits an online application the application goes through the following states

1. Online Application Submitted:

The application was received.  A copy of the application form (in PDF) must be downloaded.

2. Application Received and Under Scrutiny:

The Zonal GATE office has received the posted hard copy.  In case an application has been sent but not received for more than 10 days, please check the Speed Post website for the tracking the consignment.

3. Application Accepted:

The application has been scrutinized and found to be eligible to take the GATE 2013 examination.  The candidate has to wait till 5 Dec 2012 when the Admit Card will be available for download.

4. Rectification Required:

The application is incomplete or defective. Read the instructions given and take actions accordingly. The response must reach the Zonal office within 10 days of receipt of the mail from GATE office or November 5 which ever is earlier.

5. Provisionally Accepted:

The application has been provisionally accepted, subject to additional documents to be submitted.  Admit card for GATE 2013 will be issued, but the candidate must bring a copy of the document mentioned or a Demand Draft for Rs.600, in favour of “Chairman GATE 2013″ to the examination center; otherwise the Score Card will not be issued.

GATE 2013 Admit Card

When I will receive admit card?

Admit card can only be downloaded from the GATE Online Applicant Interface from 5th December 2012. Sending Admit cards by post has been discontinued.

Note:  For Examination bring downloaded admit card along with at least one original (not photocopied / scanned copy) and valid (not expired) photo identification.

One of the following photo identifications is permitted:

COMPARISION BASED PROBLEM 3

Question:

In an examination, Raj got more marks than Mukesh but not as many as Priya.Priya got more marks than Dinesh and Kamal. Dinesh got less marks than Mukesh but his marks are not the lowest in the group.

Who is the second in the descending order of marks?

(a) Priya (b) Kamal (c) Raj

(d) Cannot be determine (e) None of these

Explanation:

Answer is (c)

In terms of marks obtained

Mukesh < Raj, Raj < Priya, Dinesh < Priya, Kamal < Priya,

Dinesh < Mukesh.

Since Dinesh marks are not the lowest, so Kamal's marks are the

lowest.

So, the sequence becomes: Kamal < Dinesh < Mukesh < Raj < Priya.

There fore, in the descending order, Raj comes second.

COMPARISION BASED PROBLEM 2

Question:

Five children were administrated psychological tests to know their intellectual levels. In the report, psychologists pointed out that the child A is less intelligent than the child B. The child C is less intelligent than the child D.

The child B is less intelligent than the child C and child A is more intelligent than child E.

Which child is most intelligent?

(a) A (b) B

(c) D (d) E

Explanation:

Answer is (c)

We have A < B, C < D, B < C and A>E.

So, the sequence will be: E < A < B < C < D.

There fore, child D is most intelligent.

COMPARISION BASED PROBLEM 1

Question:

Compare the knowledge of persons X, Y, Z, A, B and C in relation to each other.

1.X knows more than A.

2.Y knows as much as B.

3.A knows more than C.

4.A knows more than Y.

Who is most knowledgeable person amongst all is:

(a) X (b) Y

(c) A (d) C

Explanation:

Answer is (a)

We have : X>A, Y = B, A > C, A>Y and

Now as X>A and A>C there fore X>A>C then third and forth option is not possible, as X>A and A>Y there fore X>Y then second is also not possible

There fore first option is correct.

So, X is the best knowledgeable person.